Question:
If A=bmatrix2&0&0
2&2&0
2&2&2bmatrix, then det(adj A) is equal to:
If A=bmatrix2&0&0
2&2&0
2&2&2bmatrix, then det(adj A) is equal to:
2&2&0
2&2&2bmatrix, then det(adj A) is equal to:
Show Hint
For an n× n matrix, det(adj A)=(det A)ⁿ⁻¹.
Updated On: Mar 18, 2026
- 8bmatrix1&0&0
1&1&0
1&1&1bmatrix - 16bmatrix1&0&0
1&1&0
1&1&1bmatrix - 64bmatrix1&0&0
1&1&0
1&1&1bmatrix - None of these
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Determinant of A. det A = 2·2·2 = 8
Step 2: Property of adjoint. det(adj A) = (det A)ⁿ⁻¹
Step 3: Substitution. det(adj A) = 8² = 64 = 16 × 4
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