Step 1: Understanding the Concept:
For $x \to 0^+$, $x>0$ and very small. Then $[x] = 0$ and $\frac{x}{|x|} = 1$.
Step 2: Detailed Explanation:
As \(x \to 0^+\), \([x] = 0\) and \(\frac{x}{|x|} = \frac{x}{x} = 1\).
\[
\lim_{x \to 0^+} \left[ 2[x] - \frac{x}{|x|} \right] = 2(0) - 1 = -1
\]
Step 3: Final Answer:
The limit is \(-1\).