Question:
If \( |x + 3| + x>1 \), then \( x \in \):
If \( |x + 3| + x>1 \), then \( x \in \):
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When solving inequalities involving absolute values, split the inequality into cases based on the sign of the expression inside the absolute value.
Updated On: Apr 8, 2026
- \( (-5, -2) \)
- \( (-1, \infty) \)
- \( (-5, -2) \cup (-1, \infty) \)
- None of these
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The Correct Option is C
Solution and Explanation
To solve the inequality, first break it into cases based on the absolute value. After solving, we get \( x \in (-5, -2) \cup (-1, \infty) \).
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