Question:
If \( x^2 + 2x + 7<6 \), \( x \in \mathbb{R} \), then:
If \( x^2 + 2x + 7<6 \), \( x \in \mathbb{R} \), then:
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To solve quadratic inequalities, first solve the equality and then analyze the sign of the quadratic expression.
Updated On: Jan 6, 2026
- \( x>11 \) or \( x<-3/2 \)
- \( x>11 \) or \( x<-1 \)
- \( -3/2<x<-1 \)
- \( -1<x<11 \)
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The Correct Option is D
Solution and Explanation
Step 1: Solve the inequality.
Solving the quadratic inequality \( x^2 + 2x + 7<6 \), we find that the solution is \( -1<x<11 \).
Step 2: Conclusion.
Thus, the correct answer is \( -1<x<11 \).
Final Answer: \[ \boxed{-1<x<11} \]
Solving the quadratic inequality \( x^2 + 2x + 7<6 \), we find that the solution is \( -1<x<11 \).
Step 2: Conclusion.
Thus, the correct answer is \( -1<x<11 \).
Final Answer: \[ \boxed{-1<x<11} \]
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