Question:
If we choose velocity \(V\), length \(L\) and force \(F\) as fundamental physical quantities, then how would you express power in terms of \(V\), \(L\) and \(F\)?
If we choose velocity \(V\), length \(L\) and force \(F\) as fundamental physical quantities, then how would you express power in terms of \(V\), \(L\) and \(F\)?
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Power can be written as \(P=FV\), because power is force multiplied by velocity.
Updated On: May 7, 2026
- \(F^1L^0V^1\)
- \(F^1L^{-1}V^1\)
- \(F^1L^{-1}V^2\)
- \(F^1L^{-2}V^3\)
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The Correct Option is A
Solution and Explanation
Concept:
Power is the rate of doing work. Work is defined as force multiplied by displacement.
Step 1: Formula for work is: \[ W=F\times L \]
Step 2: Power is work done per unit time: \[ P=\frac{W}{t} \]
Step 3: Substitute \(W=FL\): \[ P=\frac{FL}{t} \]
Step 4: Velocity is: \[ V=\frac{L}{t} \]
Step 5: Therefore: \[ P=F\cdot V \]
Step 6: In terms of \(F,L,V\): \[ P=F^1L^0V^1 \] \[ \boxed{F^1L^0V^1} \]
Power is the rate of doing work. Work is defined as force multiplied by displacement.
Step 1: Formula for work is: \[ W=F\times L \]
Step 2: Power is work done per unit time: \[ P=\frac{W}{t} \]
Step 3: Substitute \(W=FL\): \[ P=\frac{FL}{t} \]
Step 4: Velocity is: \[ V=\frac{L}{t} \]
Step 5: Therefore: \[ P=F\cdot V \]
Step 6: In terms of \(F,L,V\): \[ P=F^1L^0V^1 \] \[ \boxed{F^1L^0V^1} \]
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