Step 1: Find the total number of outcomes.
For 3 coins,
\[
n(S)=2^3=8
\]
Sample space:
\[
\{HHH,HHT,HTH,THH,HTT,THT,TTH,TTT\}
\]
Step 2: Count favourable outcomes.
Exactly one Head and two Tails occur in:
\[
HTT,\quad THT,\quad TTH
\]
Number of favourable outcomes
\[
n(E)=3
\]
Step 3: Calculate probability.
\[
P(E)
=
\frac{n(E)}{n(S)}
=
\frac{3}{8}
\]