Question:

If the radius of a planet is three times the radius of the earth. Both have same mass-densities. \( v_P \) and \( v_E \) are the escape velocities of the planet and the earth respectively, then

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For same density planets: \( v \propto R \). Bigger planet $\longrightarrow$ higher escape velocity.
Updated On: Apr 22, 2026
  • \( v_P = 1.5v_E \)
  • \( v_P = 3v_E \)
  • \( v_E = 2v_P \)
  • \( v_P = 2v_E \)
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The Correct Option is B

Solution and Explanation

Concept: Escape velocity: \[ v = \sqrt{\frac{2GM}{R}} \] For same density: \[ M \propto R^3 \]

Step 1:
Relate mass and radius.
\[ \frac{M_P}{M_E} = \left(\frac{R_P}{R_E}\right)^3 = 3^3 = 27 \]

Step 2:
Use escape velocity formula.
\[ v \propto \sqrt{\frac{M}{R}} \] \[ \frac{v_P}{v_E} = \sqrt{\frac{M_P/R_P}{M_E/R_E}} = \sqrt{\frac{27/3}{1}} = \sqrt{9} = 3 \]

Step 3:
Final relation.
\[ v_P = 3v_E \]
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