The area of a circle is given by the formula:
\[
A = \pi r^2
\]
where \( r \) is the radius of the circle.
Step 1: Find the sum of the areas of the two circles.
For the first circle, with radius \( r_1 = 4 \) cm, the area is:
\[
A_1 = \pi (4)^2 = 16\pi \, \text{sq. cm}
\]
For the second circle, with radius \( r_2 = 3 \) cm, the area is:
\[
A_2 = \pi (3)^2 = 9\pi \, \text{sq. cm}
\]
Now, the sum of the areas of the two circles is:
\[
A_{\text{total}} = A_1 + A_2 = 16\pi + 9\pi = 25\pi \, \text{sq. cm}
\]
Step 2: Set the area of the new circle equal to the sum of the areas.
Let the radius of the new circle be \( r \). The area of the new circle is:
\[
A_{\text{new}} = \pi r^2
\]
Since the areas are equal:
\[
\pi r^2 = 25\pi
\]
Step 3: Solve for \( r \).
Dividing both sides by \( \pi \):
\[
r^2 = 25
\]
Taking the square root of both sides:
\[
r = 5 \, \text{cm}
\]
Step 4: Conclusion.
Therefore, the radius of the new circle is 5 cm.