The product of $\sqrt{2}$ and $(2-\sqrt{2})$ will be:
Step 1: Multiply the given terms
\[
\sqrt{2} \times (2-\sqrt{2}) = \sqrt{2} \times 2 - \sqrt{2} \times \sqrt{2}
\]
\[
= 2\sqrt{2} - 2
\]
Step 2: Classify the result
The expression $2\sqrt{2} - 2$ is the difference of an irrational number ($2\sqrt{2}$) and a rational number ($2$).
Thus, the result is irrational.
\[
\boxed{2\sqrt{2} - 2 \ \text{is irrational}}
\]
If a tangent $PQ$ at a point $P$ of a circle of radius $5 \,\text{cm}$ meets a line through the centre $O$ at a point $Q$ so that $OQ = 12 \,\text{cm}$, then length of $PQ$ will be:
In the figure $DE \parallel BC$. If $AD = 3\,\text{cm}$, $DE = 4\,\text{cm}$ and $DB = 1.5\,\text{cm}$, then the measure of $BC$ will be: