Question:
If the potential difference between two points separated by a distance in a uniform electric field of 800 \(NC^{-1}\) is 16 V, then the distance of separation (in cm) is.
If the potential difference between two points separated by a distance in a uniform electric field of 800 \(NC^{-1}\) is 16 V, then the distance of separation (in cm) is.
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Always check if the answer requires meters or centimeters.
Updated On: Apr 27, 2026
- 2.0
- 3.0
- 1.5
- 2.5
- 1.0
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The Correct Option is A
Solution and Explanation
Step 1: Concept
The relationship between electric field ($E$), potential difference ($V$), and distance ($d$) is $V = Ed$.
Step 2: Meaning
Distance $d = V / E$.
Step 3: Analysis
$d = 16 / 800 = 0.02$ m. To convert to cm: $0.02 \times 100 = 2.0$ cm.
Step 4: Conclusion
Hence, the distance of separation is 2.0 cm.
Final Answer: (A)
The relationship between electric field ($E$), potential difference ($V$), and distance ($d$) is $V = Ed$.
Step 2: Meaning
Distance $d = V / E$.
Step 3: Analysis
$d = 16 / 800 = 0.02$ m. To convert to cm: $0.02 \times 100 = 2.0$ cm.
Step 4: Conclusion
Hence, the distance of separation is 2.0 cm.
Final Answer: (A)
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