Question:
If the peak voltage of message signal is \(60\%\) less than the peak voltage of the carrier wave, then the modulation index is
If the peak voltage of message signal is \(60\%\) less than the peak voltage of the carrier wave, then the modulation index is
Show Hint
For amplitude modulation,
\[
\boxed{
m=\frac{V_m}{V_c}.
}
\]
If the message signal is \(x\%\) of the carrier signal, then
\[
\boxed{
m=\frac{x}{100}.
}
\]
Updated On: Jul 18, 2026
- \(0.3\)
- \(0.4\)
- \(0.6\)
- \(0.2\)
Show Solution
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The Correct Option is B
Solution and Explanation
Step 1: Recall the definition of modulation index.
The modulation index is
\[
m=\frac{V_m}{V_c},
\]
where
\[
V_m
=
\text{peak voltage of the message signal},
\]
and
\[
V_c
=
\text{peak voltage of the carrier wave}.
\]
Step 2: Find the message signal amplitude. The message signal is \(60\%\) less than the carrier signal. Hence, \[ V_m = 40\%\text{ of }V_c = 0.4V_c. \] Therefore, \[ m = \frac{0.4V_c}{V_c} = 0.4. \]
Step 3: Write the answer. Hence, \[ \boxed{0.4}. \] Thus, \[ \boxed{(B)} \] is the correct answer.
Step 2: Find the message signal amplitude. The message signal is \(60\%\) less than the carrier signal. Hence, \[ V_m = 40\%\text{ of }V_c = 0.4V_c. \] Therefore, \[ m = \frac{0.4V_c}{V_c} = 0.4. \]
Step 3: Write the answer. Hence, \[ \boxed{0.4}. \] Thus, \[ \boxed{(B)} \] is the correct answer.
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