Question:
If the osmotic pressure of a 0.010 M aqueous solution of sucrose at 27$^\circ$C is 0.25 atm, then the osmotic pressure of a 0.010 M aqueous solution of NaCl at 27$^\circ$C is
If the osmotic pressure of a 0.010 M aqueous solution of sucrose at 27$^\circ$C is 0.25 atm, then the osmotic pressure of a 0.010 M aqueous solution of NaCl at 27$^\circ$C is
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Electrolytes increase osmotic pressure due to dissociation.
Updated On: Apr 23, 2026
- 0.062 atm
- 0.12 atm
- 0.25 atm
- 0.50 atm
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Concept:
\[
\pi = iCRT
\]
Step 1: For sucrose, $i = 1$ (non-electrolyte).
Step 2: For NaCl, $i \approx 2$ (Na$^+$ + Cl$^-$).
Step 3: Osmotic pressure $\propto$ $i$.
Step 4: Therefore, \[ \pi_{\text{NaCl}} = \textcolor{red}{2 \times 0.25 = 0.50\ \text{atm}} \] Conclusion:
Osmotic pressure = 0.50 atm
Step 1: For sucrose, $i = 1$ (non-electrolyte).
Step 2: For NaCl, $i \approx 2$ (Na$^+$ + Cl$^-$).
Step 3: Osmotic pressure $\propto$ $i$.
Step 4: Therefore, \[ \pi_{\text{NaCl}} = \textcolor{red}{2 \times 0.25 = 0.50\ \text{atm}} \] Conclusion:
Osmotic pressure = 0.50 atm
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