Concept:
For electrons, Hall coefficient is:
\[
R_H=-\frac{1}{ne}
\]
where,
\[
n=\text{number of electrons per unit volume}
\]
and
\[
e=1.6\times10^{-19}\ \text{C}
\]
Step 1: Write the given value.
\[
n=2.55\times10^{28}\ \text{m}^{-3}
\]
Step 2: Apply the formula.
\[
R_H=-\frac{1}{ne}
\]
\[
R_H=-\frac{1}{(2.55\times10^{28})(1.6\times10^{-19})}
\]
\[
R_H=-\frac{1}{4.08\times10^9}
\]
\[
R_H=-2.45\times10^{-10}\ \text{m}^3/\text{C}
\]
\[
\therefore \text{Correct Answer is (C)}
\]