Question:

If the maximum acceleration of a moving platform to keep a box of mass \(5\) kg on it without sliding is \(3\ \text{m s}^{-2}\), then the static friction between the box and floor of the platform is (\(g = 10\ \text{m s}^{-2}\))

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For no slipping condition: - $\mu_s = \frac{a}{g}$ - Mass cancels out, so value is independent of mass
Updated On: Apr 30, 2026
  • $0.15$
  • $0.25$
  • $0.30$
  • $0.35$
  • $0.4$
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The Correct Option is C

Solution and Explanation

Concept: For a body on an accelerating surface without slipping: \[ f_{\text{max}} = \mu_s N \] Also, friction provides the necessary acceleration: \[ ma = f_{\text{max}} \]

Step 1:
Write the force equation.
\[ ma = \mu_s mg \]

Step 2:
Cancel mass $m$.
\[ a = \mu_s g \]

Step 3:
Solve for $\mu_s$.
\[ \mu_s = \frac{a}{g} = \frac{3}{10} = 0.3 \]
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