If the maximum acceleration of a moving platform to keep a box of mass \(5\) kg on it without sliding is \(3\ \text{m s}^{-2}\), then the static friction between the box and floor of the platform is (\(g = 10\ \text{m s}^{-2}\))
Show Hint
For no slipping condition:
- $\mu_s = \frac{a}{g}$
- Mass cancels out, so value is independent of mass
Concept:
For a body on an accelerating surface without slipping:
\[
f_{\text{max}} = \mu_s N
\]
Also, friction provides the necessary acceleration:
\[
ma = f_{\text{max}}
\]
Step 1: Write the force equation.
\[
ma = \mu_s mg
\]
Step 2: Cancel mass $m$.
\[
a = \mu_s g
\]
Step 3: Solve for $\mu_s$.
\[
\mu_s = \frac{a}{g} = \frac{3}{10} = 0.3
\]