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if the kinetic energy of a moving body reduces to
Question:
If the kinetic energy of a moving body reduces to \(49\%\), then its velocity is reduced to
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If KE becomes \(k\) times, velocity becomes \(\sqrt{k}\) times.
KEAM - 2025
KEAM
Updated On:
Apr 24, 2026
\(49\%\)
\(70\%\)
\(30\%\)
\(25\%\)
\(51\%\)
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Verified By Collegedunia
The Correct Option is
B
Solution and Explanation
Step 1:
Understanding the Concept:
Kinetic energy \(KE = \frac{1}{2}mv^2\). So \(KE \propto v^2\).
Step 2:
Detailed Explanation:
\(\frac{KE_2}{KE_1} = \frac{49}{100} = 0.49\)
\(\frac{v_2^2}{v_1^2} = 0.49 \Rightarrow \frac{v_2}{v_1} = \sqrt{0.49} = 0.7 = 70\%\)
Step 3:
Final Answer:
Velocity is reduced to \(70\%\).
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