Question:

If the instantaneous displacement of a wave is $y = 2(\sin 2\pi t + \sqrt{3}\cos 2\pi t)\,cm$, then the amplitude of the wave in $cm$ is

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Amplitude of $a\sin\theta + b\cos\theta$ is $\sqrt{a^2 + b^2}$.
Updated On: Apr 24, 2026
  • $4$
  • $3$
  • $5$
  • $2$
  • $6$
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The Correct Option is A

Solution and Explanation

Concept:
• Expression of form: \[ a\sin\theta + b\cos\theta = R\sin(\theta + \phi) \] where $R = \sqrt{a^2 + b^2}$

Step 1:
Identify coefficients
\[ a = 2,\quad b = 2\sqrt{3} \]

Step 2:
Amplitude
\[ R = \sqrt{2^2 + (2\sqrt{3})^2} \] \[ = \sqrt{4 + 12} = \sqrt{16} = 4 \] Final Conclusion:
\[ = 4 \]
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