Question:

If the distance between sun and earth is \(d\), then the angular momentum of earth around the sun is proportional to

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For orbital motion: \[ v=\sqrt{\frac{GM}{r}} \] Then substitute into \[ L=mvr \] to get the dependence on \(r\).
Updated On: Apr 29, 2026
  • \(\sqrt{d}\)
  • \(d\)
  • \(d^{3/2}\)
  • \(d^2\)
  • \(d^{-1/2}\)
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The Correct Option is C

Solution and Explanation

Angular momentum: \[ L = mvr \] For circular orbit: \[ v=\sqrt{\frac{GM}{r}} \] So, \[ L = mr\sqrt{\frac{GM}{r}} = m\sqrt{GMr} \] Thus, \[ L\propto \sqrt{r} \] If \(r=d\), then: \[ L\propto d^{1/2} \] So the direct calculation gives: \[ \boxed{\sqrt{d}} \] which corresponds to option (A), not (C).
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