Question:
If the diatomic molecule is non-rigid, then its molar specific heat capacity at constant volume is
If the diatomic molecule is non-rigid, then its molar specific heat capacity at constant volume is
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For rigid diatomic molecules, $f=5$ and $C_v = \frac{5}{2}R$. Vibration only counts for non-rigid molecules.
Updated On: Apr 27, 2026
- $\frac{5}{2}R$
- $\frac{7}{2}R$
- $\frac{1}{2}R$
- $\frac{9}{2}R$
- $\frac{3}{2}R$
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The Correct Option is B
Solution and Explanation
Step 1: Concept
The molar specific heat at constant volume is $C_v = \frac{f}{2}R$, where $f$ is the degrees of freedom.
Step 2: Meaning
A "non-rigid" diatomic molecule has 3 translational, 2 rotational, and 2 vibrational degrees of freedom.
Step 3: Analysis
Total $f = 3 + 2 + 2 = 7$. Therefore, $C_v = \frac{7}{2}R$.
Step 4: Conclusion
Hence, the specific heat capacity is $\frac{7}{2}R$.
Final Answer: (B)
The molar specific heat at constant volume is $C_v = \frac{f}{2}R$, where $f$ is the degrees of freedom.
Step 2: Meaning
A "non-rigid" diatomic molecule has 3 translational, 2 rotational, and 2 vibrational degrees of freedom.
Step 3: Analysis
Total $f = 3 + 2 + 2 = 7$. Therefore, $C_v = \frac{7}{2}R$.
Step 4: Conclusion
Hence, the specific heat capacity is $\frac{7}{2}R$.
Final Answer: (B)
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