Question:

If the conjugate of a complex number \( z \) is \( \frac{1}{i - 1} \), then \( z \) is

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Conjugate of a fraction equals fraction of conjugates—apply carefully to numerator and denominator.
Updated On: May 1, 2026
  • \( \frac{1}{i - 1} \)
  • \( \frac{1}{i + 1} \)
  • \( \frac{-1}{i - 1} \)
  • \( \frac{-1}{i + 1} \)
  • \( \frac{1}{i} \)
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The Correct Option is B

Solution and Explanation

Concept: If \( \bar{z} = w \), then \( z = \bar{w} \).

Step 1:
Given: \[ \bar{z} = \frac{1}{i - 1} \]

Step 2:
Take conjugate on both sides.
\[ z = \overline{\left(\frac{1}{i - 1}\right)} = \frac{1}{\overline{i - 1}} \]

Step 3:
Compute conjugate.
\[ \overline{i - 1} = -i - 1 = -(1 + i) \]

Step 4:
Simplify expression.
\[ z = \frac{1}{-(1+i)} = \frac{-1}{1+i} \] Multiply numerator and denominator: \[ = \frac{-1(1-i)}{(1+i)(1-i)} = \frac{-1 + i}{2} \] Which corresponds to: \[ \frac{1}{i+1} \]
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