Step 1: Understanding the Question:
We are given the acute angle $\theta = \frac{\pi}{4}$ ($45^\circ$) between two intersecting lines, along with the slope of the first line ($m_1 = \frac{1}{2}$). We need to find the possible values for the slope of the second line ($m_2$).
Step 2: Key Formula or Approach:
The standard formula relating the acute angle $\theta$ between two intersecting lines to their slopes $m_1$ and $m_2$ is:
$$\tan\theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|$$
Removing the absolute value bars introduces a $\pm$ sign on the opposite side of the equation.
Step 3: Detailed Explanation:
Substitute the given values $\theta = 45^\circ$ and $m_1 = \frac{1}{2}$ into the angle formula:
$$\tan(45^\circ) = \left| \frac{\frac{1}{2} - m_2}{1 + \frac{1}{2}m_2} \right|$$
Since $\tan(45^\circ) = 1$, we can simplify the expression inside the absolute value:
$$\left| \frac{1 - 2m_2}{2 + m_2} \right| = 1 \implies \frac{1 - 2m_2}{2 + m_2} = \pm 1$$
This yields two separate algebraic cases to solve for $m_2$:
• Case 1: Positive Sign (+1)
$$\frac{1 - 2m_2}{2 + m_2} = 1 \implies 1 - 2m_2 = 2 + m_2$$
$$-1 = 3m_2 \implies m_2 = -\frac{1}{3}$$
• Case 2: Negative Sign (-1)
$$\frac{1 - 2m_2}{2 + m_2} = -1 \implies 1 - 2m_2 = -(2 + m_2)$$
$$1 - 2m_2 = -2 - m_2 \implies 3 = m_2 \implies m_2 = 3$$
Thus, the possible values for the slope of the second line are $3$ or $-\frac{1}{3}$.
Step 4: Final Answer:
The slope of the other line is $3$ or $-\frac{1}{3}$, which corresponds to option (A).