Step 1: Understand the concept
At 298 K, the ion product of water gives \(\text{pH} + \text{pOH} = 14\). So we need the pH first.
Step 2: Find pH
\[ \text{pH} = -\log(1 \times 10^{-4}) = 4 \]
Step 3: Find pOH
\[ \text{pOH} = 14 - 4 = 10 \]
Step 4: Check the options
The value 4 is the pH, not the pOH, so (A) is a mix-up. The value 12 would mean pH 2, and 14 would mean pH 0. Neither fits a hydronium concentration of \(10^{-4}\) M. The solution is acidic, so the pOH must be larger than 7, and 10 satisfies this.
Final Answer:
The pOH is 10. This is option (B).
\[ \boxed{\text{(B) }10} \]