Question:
If $\phi_A$ and $\phi_B$ are the electric fluxes leaving and entering a Gaussian surface respectively, then the charge enclosed is:
If $\phi_A$ and $\phi_B$ are the electric fluxes leaving and entering a Gaussian surface respectively, then the charge enclosed is:
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Outward flux is positive and inward flux is negative.
Updated On: Jun 17, 2026
- $(\phi_A - \phi_B)\epsilon_0$
- $\frac{\phi_A + \phi_B}{\epsilon_0}$
- $(\phi_A + \phi_B)\epsilon_0$
- $\frac{\phi_B - \phi_A}{\epsilon_0}$
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The Correct Option is A
Solution and Explanation
Step 1: By Gauss’s law: \[ \Phi = \frac{q_{\text{enc}}}{\epsilon_0} \]
Step 2: Net flux is algebraic sum of outward and inward flux: \[ \Phi_{\text{net}} = \phi_A - \phi_B \]
Step 3: Substituting in Gauss law: \[ q_{\text{enc}} = \epsilon_0 (\phi_A - \phi_B) \]
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