Question:

If \[ \log_a 2+\log_a 5=1, \] then the value of \(a\) is:

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If \[ \log_a b=1, \] then immediately conclude that \[ a=b, \] because \[ a^1=b. \] This shortcut frequently appears in logarithmic equations.
Updated On: Jun 10, 2026
  • \(7\)
  • \(10\)
  • \(12\)
  • \(15\)
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The Correct Option is B

Solution and Explanation

Concept: Logarithms obey several important laws which simplify complicated expressions. One of the most frequently used logarithmic identities is \[ \log_a m+\log_a n=\log_a(mn). \] This property allows us to combine two logarithmic terms having the same base into a single logarithm. After combining the logarithms, we can convert the logarithmic equation into exponential form and solve it directly. Whenever a logarithmic equation contains only one logarithm after simplification, converting to exponential form is generally the most efficient method.

Step 1: Write the given equation. We are given \[ \log_a2+\log_a5=1. \]

Step 2: Apply the logarithmic addition property. Using \[ \log_a m+\log_a n=\log_a(mn), \] we obtain \[ \log_a(2\times5)=1. \] Hence, \[ \log_a(10)=1. \]

Step 3: Convert the logarithmic equation into exponential form. The statement \[ \log_a(10)=1 \] means \[ a^1=10. \]

Step 4: Simplify. Since any number raised to the power \(1\) remains unchanged, \[ a=10. \]

Step 5: Verification. Substituting \(a=10\), \[ \log_{10}2+\log_{10}5 = \log_{10}(10) = 1. \] The given condition is satisfied.

Step 6: Final Conclusion. Therefore, \[ \boxed{a=10} \] Hence the correct answer is \[ \boxed{\text{Option (B)}}. \]
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