Question:

If in English Alphabet 'e' and every alternate letter from 'e' onwards is written in Capitals, then how will sixth month from March will be coded

Updated On: Jul 15, 2026
  • SEPTEmbER
  • SEptEMbEr
  • SepTeMber
  • SEPtEmbER
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The Correct Option is B

Approach Solution - 1

The correct option is (B): SEptEMbEr.
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Approach Solution -2

The rule capitalises 'e' and every alternate letter counting onward from 'e' in the alphabet, giving the capital set e, g, i, k, m, o, q, s, u, w, y, while every other letter stays lower-case. The month asked for is the sixth month counting from March: April (1), May (2), June (3), July (4), August (5), September (6), so the target word is 'september'. Applying the rule letter by letter gives S, E, p, t, E, M, b, E, r, that is 'SEptEMbEr'. Let's check each option against this:

  1. Option A (SEPTEmbER): capitalises P and T, which are not in the capital set, and also capitalises the final 'ER' though r is not in the set either, this breaks the rule at multiple letters.
  2. Option B (SEptEMbEr): S, E capital; p, t lower; E capital; M capital; b lower; E capital; r lower, every single letter matches the capitalisation rule in order.
  3. Option C (SepTeMber): wrongly capitalises T, which should stay lower-case, and leaves the fifth letter (the second 'e') lower-case though it should be capital.
  4. Option D (SEPtEmbER): capitalises P, which is not in the set, and also wrongly capitalises the final 'ER'.

Only option B applies the rule consistently to every letter of 'september'.

Therefore, the correct answer is SEptEMbEr.

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Approach Solution -3

The rule can be restated as a position test: numbering the alphabet A = 1 through Z = 26, a letter is capitalised only if its position is odd AND at least 5, that is positions 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25 (e, g, i, k, m, o, q, s, u, w, y), every other position stays lower-case. The sixth month counting from March, April (1), May (2), June (3), July (4), August (5), September (6), is September, so the base word is 'september'. Testing each letter's position against the rule: s = 19 (odd, >= 5, capital), e = 5 (odd, >= 5, capital), p = 16 (even, lower), t = 20 (even, lower), e = 5 (capital), m = 13 (odd, >= 5, capital), b = 2 (even, lower), e = 5 (capital), r = 18 (even, lower), giving S, E, p, t, E, M, b, E, r.

  1. Option A (SEPTEmbER): capitalises p (16, even) and t (20, even) as P and T, and also capitalises the final r (18, even) as R, all three fail the odd-and-at-least-5 test.
  2. Option B (SEptEMbEr): every capital letter, S, E, E, M, E, sits at an odd position of 5 or more, and every lower-case letter, p, t, b, r, sits at an even position, matching the test at all nine letters.
  3. Option C (SepTeMber): capitalises t (20, even) as T, which fails the test, and leaves the second e (position 5, odd, >= 5) in lower-case, though it should be capital.
  4. Option D (SEPtEmbER): capitalises p (16, even) as P, and wrongly capitalises the final r (18, even) as R, both fail the odd-and-at-least-5 requirement.

Only option B has every letter's case matching whether its alphabet position is odd and at least 5.

Therefore, the correct answer is SEptEMbEr.

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