Rule from the example.
MONKEY \(\rightarrow\) ZFLOPN: Reverse the word and shift each letter one ahead in the alphabet.
Check: \(\text{MONKEY} \xrightarrow{\text{reverse}} \text{YEKNOM} \xrightarrow{+1} \text{ZFLOPN}\).
Apply to CHARACTER.
\[ \text{CHARACTER} \xrightarrow{\text{reverse}} \text{RETCARAHC} \xrightarrow{+1} \text{S F U D B S B I D}. \] Thus the code is \(\boxed{\text{SFUDBSBID}}\).
Instead of reversing the word first and then shifting, let's shift every letter forward by one first and reverse the result afterward — the two operations commute, so this order should give an independent check on the same rule.
Shift each letter of \(\text{CHARACTER}\) forward by one: \[ C{\to}D,\ H{\to}I,\ A{\to}B,\ R{\to}S,\ A{\to}B,\ C{\to}D,\ T{\to}U,\ E{\to}F,\ R{\to}S, \] giving \(\text{DIBSBDUFS}\). Reversing this string end-to-end produces \(\text{SFUDBSBID}\).
Shifting first and reversing afterward reproduces exactly the same coded word.
Hence, the correct answer is SFUDBSBID.
