Question

If \( I = 2 \, \text{A}, \, \phi = 10^{-2} \, \text{Weber}, \, N = 1000 \), calculate the self-inductance.

Hint:

The self-inductance of a coil can be calculated using the formula \( L = \frac{N \cdot \phi}{I} \), which relates the flux, current, and number of turns.

Answer 1

Step 1: Formula for self-inductance.
The self-inductance \( L \) of a coil is given by the formula: \[ L = \frac{N \cdot \phi}{I} \] where:
- \( N \) is the number of turns,
- \( \phi \) is the magnetic flux,
- \( I \) is the current.

Step 2: Substitute the given values.
We are given: \[ I = 2 \, \text{A}, \quad \phi = 10^{-2} \, \text{Weber}, \quad N = 1000 \] Substitute these values into the formula: \[ L = \frac{1000 \cdot 10^{-2}}{2} = \frac{10}{2} = 5 \, \text{Henrys} \]