Question:
If force is proportional to square of velocity, then the dimensions of proportionality constant is
If force is proportional to square of velocity, then the dimensions of proportionality constant is
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If force is proportional to square of velocity, then the dimensions of proportionality constant is
Updated On: Apr 15, 2026
- $[ML^{-1}T]$
- $[ML^{-1}T^0]$
- $[MLT^0]$
- $[M^0LT^{-1}]$
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The Correct Option is B
Solution and Explanation
Step 1: Equation
$F = kv^2 \Rightarrow k = F/v^2$.
Step 2: Dimensions
$[F] = [MLT^{-2}]$ and $[v] = [LT^{-1}]$.
Step 3: Calculation
$[k] = \frac{[MLT^{-2}]}{[L^2T^{-2}]} = [ML^{-1}T^0]$.
Final Answer: (B)
$F = kv^2 \Rightarrow k = F/v^2$.
Step 2: Dimensions
$[F] = [MLT^{-2}]$ and $[v] = [LT^{-1}]$.
Step 3: Calculation
$[k] = \frac{[MLT^{-2}]}{[L^2T^{-2}]} = [ML^{-1}T^0]$.
Final Answer: (B)
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