If force is proportional to square of velocity, then the dimensions of proportionality constant is
Show Hint
- [ML\(^{-1}\)T]
- [ML\(^{-1}\)T\(^0\)]
- [MLT]
- [M\(^0\)LT\(^{-1}\)]
The Correct Option is B
Solution and Explanation
From \(F = kv^2\), find dimensions of k.
Step 2: Detailed Explanation:
\(k = F/v^2 \rightarrow [\mathrm{MLT}^{-2}]/[\mathrm{L}^2\mathrm{T}^{-2}] = [\mathrm{ML}^{-1}\mathrm{T}^0]\)
Step 3: Final Answer:
Dimensions are \([\mathrm{ML}^{-1}\mathrm{T}^0]\).
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