Question:

If \[ \Delta_r = \begin{vmatrix} 1 & n & n \\ 2r & n^2+n+1 & n^2+n \\ 2r-1 & n^2 & n^2+n+1 \end{vmatrix} \] and \( \sum_{r=1}^{n} \Delta_r = 56 \), then \( n \) is

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Use linearity of determinant to simplify summation problems.
Updated On: Apr 23, 2026
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The Correct Option is C

Solution and Explanation

Concept: Determinant linearity with respect to rows.

Step 1:
Expand determinant.
$\Delta_r$ becomes linear in $r$.

Step 2:
Use summation formula.
\[ \sum r = \frac{n(n+1)}{2} \]

Step 3:
Simplify total sum.
Expression reduces to polynomial in $n$.

Step 4:
Solve equation.
\[ \sum \Delta_r = 56 \Rightarrow n = 7 \] Conclusion:
$n = 7$
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