Step 1: Split
On \([1,2)\), \([x]=1\); on \([2,3)\), \([x]=2\); on \([3,4)\), \([x]=3\).
Step 2: Integrate each part
\[ \int_1^2x\,dx=\frac{4-1}{2}=\frac32 \]
\[ \int_2^32x\,dx=9-4=5 \]
\[ \int_3^43x\,dx=\frac{3(16-9)}{2}=\frac{21}{2} \]
Step 3: Add
\(\frac32+5+\frac{21}{2}=17\).
Final Answer:
The value is \(17\), option (D).
\[ \boxed{\text{(D) }17} \]