Question:

If an observer moves towards a stationary source, then the apparent frequency is given by:

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Moving towards \(\Rightarrow\) frequency increases \(\Rightarrow\) use + sign.
Updated On: Apr 16, 2026
  • \( f' = f_0 \left(\frac{v+v_o}{v}\right) \)
  • \( f' = f_0 \left(\frac{v-v_o}{v}\right) \)
  • \( f' = f_0 \left(\frac{v}{v+v_o}\right) \)
  • \( f' = f_0 \left(\frac{v}{v-v_o}\right) \)
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The Correct Option is A

Solution and Explanation

Concept: Doppler effect for moving observer: \[ f' = f_0 \left(\frac{v \pm v_o}{v}\right) \]

Step 1:
Observer moving towards source.
Use plus sign.

Step 2:
Final expression.
\[ f' = f_0 \left(\frac{v+v_o}{v}\right) \]
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