Step 1: Understanding the Question:
The question asks for the reactive power (\(Q\)) carried by a transmission line when it is delivering a specified active power (\(P\)) at a unity power factor (\(\text{pf} = 1.0\)).
Step 2: Key Formula or Approach:
In AC power systems, active power (\(P\)) and reactive power (\(Q\)) are related to the apparent power (\(S\)) and power factor angle (\(\theta\)) by:
\[ P = S \cos\theta \]
\[ Q = S \sin\theta \]
The relation between active and reactive power is:
\[ Q = P \cdot \tan\theta \]
where \(\cos\theta\) is the power factor.
Step 3: Detailed Explanation:
• Identify the given parameters:
- Active power, \(P = 100\text{ MW}\).
- Power factor, \(\cos\theta = 1.0\).
• Find the power factor angle \(\theta\):
\[ \theta = \cos^{-1}(1.0) = 0^\circ \]
• Calculate the reactive power \(Q\):
\[ Q = P \cdot \tan(0^\circ) = 100 \times 0 = 0\text{ MVAR} \]
• This shows that at unity power factor, the current and voltage are in phase, meaning no reactive power is drawn or supplied by the load.
Step 4: Final Answer:
The reactive power is 0 MVAR.