Question

If a satellite completes revolution in orbit two times a day, then angular velocity is

• A. 180°/day
• B. 360°/day
• C. 720°/day
• D. 90°/day

Hint:

Angular velocity:
- For 1 revolution: 360° (or 2\(\pi\) radians).
- For n revolutions: n × 360° per unit time.
- Unit: degrees/day or radians/day.

Answer 1

The Correct Option is C

Step 1: Understanding the Question:
This question tests the calculation of angular velocity of a satellite.

Step 2: Key Formula or Approach:
Angular velocity (\(\omega\)) is the angle covered per unit time.
For one revolution, the angle covered is 360°.

Step 3: Detailed Explanation:
The satellite completes 2 revolutions per day.
Angle covered in 1 revolution = 360°.
Angle covered in 2 revolutions = \(2 \times 360° = 720°\).
Angular velocity = 720°/day.
Other options:
- 180°/day (A): Too low.
- 360°/day (B): For 1 revolution/day.
- 90°/day (D): Too low.
Thus, angular velocity is 720°/day.
Final Answer:
Thus, the angular velocity is 720°/day, which corresponds to option (C).
[0.5cm]