Question:
If a meiocyte consists of 16 chromosomes, then the number of chromosomes and chromatids in each cell after Meiosis I will be respectively:
If a meiocyte consists of 16 chromosomes, then the number of chromosomes and chromatids in each cell after Meiosis I will be respectively:
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In Meiosis I, chromosome number halves but chromatids remain paired.
Updated On: Jun 20, 2026
- 16 and 32
- 16 and 16
- 8 and 16
- 8 and 8
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The Correct Option is C
Solution and Explanation
Step 1: Understanding meiosis I.
Meiosis I is a reductional division where the chromosome number is reduced to half.
Step 2: Initial condition.
Diploid cell (meiocyte) has 2n = 16 chromosomes.
Step 3: After Meiosis I chromosome number.
After Meiosis I, homologous chromosomes separate, so each daughter cell becomes haploid:
n = 8 chromosomes.
Step 4: Chromatid analysis.
Each chromosome still consists of two sister chromatids after Meiosis I.
So total chromatids = 8 × 2 = 16 chromatids.
Step 5: Biological reasoning.
Reductional division reduces chromosome number but does not separate sister chromatids at this stage.
Step 6: Final conclusion.
Therefore, the correct answer is: \[ \boxed{8 \text{ and } 16} \]
Meiosis I is a reductional division where the chromosome number is reduced to half.
Step 2: Initial condition.
Diploid cell (meiocyte) has 2n = 16 chromosomes.
Step 3: After Meiosis I chromosome number.
After Meiosis I, homologous chromosomes separate, so each daughter cell becomes haploid:
n = 8 chromosomes.
Step 4: Chromatid analysis.
Each chromosome still consists of two sister chromatids after Meiosis I.
So total chromatids = 8 × 2 = 16 chromatids.
Step 5: Biological reasoning.
Reductional division reduces chromosome number but does not separate sister chromatids at this stage.
Step 6: Final conclusion.
Therefore, the correct answer is: \[ \boxed{8 \text{ and } 16} \]
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