Step 1: Recall Chargaff's rule.
In double-stranded DNA, complementary base pairing occurs:
\[
A=T
\]
and
\[
G=C
\]
Therefore, after hydrolysis of double helix DNA, equal numbers of A and T as well as G and C are obtained.
Step 2: Examine m-RNA.
m-RNA is a single-stranded nucleic acid.
It contains bases
\[
A,\ U,\ G,\ C
\]
and does not contain thymine (\(T\)).
Since complementary pairing is absent throughout the molecule,
\[
A \neq U
\]
and
\[
G \neq C
\]
in general.
Hence, m-RNA does not give equal numbers of complementary bases on hydrolysis.
Step 3: Examine single-stranded DNA.
Single-stranded DNA does not possess complete complementary base pairing.
Therefore, there is no requirement that
\[
A=T
\]
or
\[
G=C
\]
Thus, hydrolysis of single-stranded DNA does not necessarily yield equal numbers of these bases.
Step 4: Examine r-RNA.
r-RNA is also predominantly single-stranded.
Hence, it does not obey Chargaff's base equivalence rule.
Therefore,
\[
A \neq U
\]
and
\[
G \neq C
\]
in general.
Step 5: Final conclusion.
Among the given nucleic acids, the ones that do not give equal numbers of complementary bases on hydrolysis are
\[
\boxed{\text{(a), (b), (c)}}
\]
Therefore, the correct option is (1).