Question:

If \(A\) is a square matrix of order \(3\) such that \( |adj\,A| = 64 \), then find the value of \( |A| \).

Show Hint

For a square matrix of order \(n\), remember the identity \[ |adj\,A| = |A|^{\,n-1}. \] In many exam problems, once the order of the matrix is known, this formula allows you to directly relate the determinant of the matrix and its adjoint.
Updated On: Apr 30, 2026
  • \(4\)
  • \(\pm 4\)
  • \(8\)
  • \(\pm 8\)
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The Correct Option is D

Solution and Explanation

Concept: For a square matrix \(A\) of order \(n\), the determinant of the adjoint matrix satisfies the property \[ |adj\,A| = |A|^{\,n-1} \] where \(n\) is the order of the matrix. This identity is frequently used in determinant problems involving adjoint matrices.

Step 1:
Use the determinant property of the adjoint matrix. Since \(A\) is a square matrix of order \(3\), \[ |adj\,A| = |A|^{3-1} \] \[ |adj\,A| = |A|^{2} \]

Step 2:
Substitute the given value. \[ |adj\,A| = 64 \] Therefore, \[ |A|^2 = 64 \]

Step 3:
Solve for the determinant of \(A\). \[ |A| = \pm \sqrt{64} \] \[ |A| = \pm 8 \]
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