Question:

If a huge tank has a small side hole at a depth of $2$ m from the surface of water, then the velocity of water flowing through the hole is ($g = 10\ \text{m s}^{-2}$)

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For fluid flow from a hole: - Use $v = \sqrt{2gh}$ - Depth $h$ is measured from liquid surface
Updated On: Apr 30, 2026
  • $2\sqrt{5}\ \text{m s}^{-1}$
  • $2\sqrt{10}\ \text{m s}^{-1}$
  • $\sqrt{10}\ \text{m s}^{-1}$
  • $4\sqrt{10}\ \text{m s}^{-1}$
  • $4\sqrt{5}\ \text{m s}^{-1}$
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The Correct Option is B

Solution and Explanation

Concept: Using Torricelli’s theorem: \[ v = \sqrt{2gh} \]

Step 1:
Substitute given values.
\[ v = \sqrt{2 \times 10 \times 2} \]

Step 2:
Simplify.
\[ v = \sqrt{40} = 2\sqrt{10}\ \text{m s}^{-1} \]
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