Question:
If a gun fires 25 bullets in one second, each of $10g$ mass with a velocity of $20\,ms^{-1}$, then the recoil force on the gun in $N$ is:
If a gun fires 25 bullets in one second, each of $10g$ mass with a velocity of $20\,ms^{-1}$, then the recoil force on the gun in $N$ is:
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Recoil force = bullets per second × momentum per bullet.
Updated On: Apr 24, 2026
- $50$
- $5$
- $15$
- $10$
- $20$
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The Correct Option is B
Solution and Explanation
Concept:
• Recoil force = rate of change of momentum
Step 1: Mass per bullet
\[ m = 10g = 0.01\,kg \]
Step 2: Momentum per bullet
\[ p = mv = 0.01 \times 20 = 0.2 \]
Step 3: Total momentum per second
\[ 25 \times 0.2 = 5 \]
Step 4: Force
\[ F = \frac{dp}{dt} = 5N \] Final Conclusion:
\[ = 5N \]
• Recoil force = rate of change of momentum
Step 1: Mass per bullet
\[ m = 10g = 0.01\,kg \]
Step 2: Momentum per bullet
\[ p = mv = 0.01 \times 20 = 0.2 \]
Step 3: Total momentum per second
\[ 25 \times 0.2 = 5 \]
Step 4: Force
\[ F = \frac{dp}{dt} = 5N \] Final Conclusion:
\[ = 5N \]
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