Step 1: Understanding the Concept:
A Wheatstone Bridge is an electrical circuit used to measure an unknown electrical resistance. It consists of four resistances arranged in a diamond shape. The bridge is said to be "balanced" when the potential difference between the middle junctions is zero, resulting in no current flow through the galvanometer.
Step 2: Identifying the Condition for Balance:
For a bridge with arms $P, Q, R,$ and $S$, the balance condition is:
\[ \frac{P}{Q} = \frac{R}{S} \]
In this state, the galvanometer shows a "null deflection."
Step 3: Detailed Explanation:
In the given problem:
• $P = 1 \, \Omega$
• $Q = 1 \, \Omega$
• $R = 1 \, \Omega$
• $S = 1 \, \Omega$
Calculating the ratios:
\[ \frac{P}{Q} = \frac{1}{1} = 1 \]
\[ \frac{R}{S} = \frac{1}{1} = 1 \]
Since $\frac{P}{Q} = \frac{R}{S}$, the bridge is perfectly balanced. Because the potential at the two junctions where the galvanometer is connected is identical, no potential difference exists to drive a current.
Step 4: Final Answer
The current flowing through the galvanometer is zero.