Question:

If \(a, b, c, d\) are inputs to a gate and \(x\) is its output, then, as per the following time graph, the gate is :

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Compare the output with the inputs at the start, when all inputs are low, and when only one input is high.
Updated On: Nov 11, 2026
  • OR
  • NAND
  • NOT
  • AND
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The Correct Option is A

Solution and Explanation

At the start all four inputs \(a, b, c, d\) are low (0) and the output \(x\) is 0.
As soon as input \(d\) goes high while \(a, b, c\) are still low, \(x\) becomes 1 and stays high.
So the output is 1 when at least one input is 1, and 0 only when all inputs are 0. This is the OR gate.
Elimination: an AND gate would give 0 when only \(d\) is high; a NAND gate would give 1 when all inputs are 0 (but \(x = 0\) initially); a NOT gate has a single input.
Answer: (1) OR
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