Question:

If a,b,c are real numbers then the roots of (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 are always

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Check discriminant to decide nature of roots.
Updated On: Mar 20, 2026
  • real
  • imaginary
  • positive
  • negative
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The Correct Option is A

Solution and Explanation


Step 1:
Simplify equation: 3x²-2(a+b+c)x+(ab+bc+ca)=0
Step 2:
Discriminant: Δ=[2(a+b+c)]²-12(ab+bc+ca)\ge0
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