Question:

If a,b are non-zero roots of x²+ax+b=0, then the least value of x²+ax+b is

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Minimum of ax²+bx+c occurs at x=-(b)/(2a).
Updated On: Mar 20, 2026
  • \( \dfrac{2}{3} \)
  • \( -\dfrac{9}{4} \)
  • \( \dfrac{9}{4} \)
  • 1
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The Correct Option is B

Solution and Explanation

The minimum value of a quadratic x²+ax+b occurs at x=-(a)/(2): min = b-(a²)/(4)=-(9)/(4)
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