Question:

If a $3 \times 3$ matrix $A$ has eigenvalues $2, 3, -4$, find $\det(A)$.

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Determinant = product of eigenvalues.
Updated On: May 20, 2026
  • $6$
  • $-12$
  • $-24$
  • $24$
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The Correct Option is C

Solution and Explanation

Concept: Determinant equals product of eigenvalues.

Step 1: Multiply eigenvalues
\[ \det(A) = 2 \times 3 \times (-4) \] \[ = 6 \times (-4) = -24 \] \[ \therefore \det(A) = -24 \]
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