Question

If a 25.0 mL sample of sulfuric acid is titrated with 50.0 mL of 0.025 M sodium hydroxide to a phenolphthalein endpoint, what is the molarity of the acid?

• A. 0.020 M
• B. 0.100 M
• C. 0.025 M
• D. 0.050 M

Hint:

Use equivalence of moles at titration end point.

Answer 1

The Correct Option is D

Moles of NaOH: 0.050 × 0.025 = 0.00125 Equivalent moles of acid =0.00125 M = (0.00125)/(0.025) = 0.05M