Question:
If a 25.0 mL sample of sulfuric acid is titrated with 50.0 mL of 0.025 M sodium hydroxide to a phenolphthalein endpoint, what is the molarity of the acid?
If a 25.0 mL sample of sulfuric acid is titrated with 50.0 mL of 0.025 M sodium hydroxide to a phenolphthalein endpoint, what is the molarity of the acid?
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Use equivalence of moles at titration end point.
Updated On: Mar 20, 2026
- 0.020 M
- 0.100 M
- 0.025 M
- 0.050 M
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Moles of NaOH:
0.050 × 0.025 = 0.00125
Equivalent moles of acid =0.00125
M = (0.00125)/(0.025) = 0.05M
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