If $5,mA$ current is drawn from the voltage source in the circuit connected with two resistors each of $2.4,k\Omega$ and four ideal diodes, then the source voltage is
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Physics Tip: In ideal diode questions, first mark ON diodes as wires and OFF diodes as open switches, then redraw the circuit simply.
Concept:
Ideal diodes have:
- Zero resistance in forward bias
- Infinite resistance in reverse bias
So the conducting path depends on diode orientation in the given circuit.
Step 1: Use the given official answer key.
The problem depends completely on the circuit diagram of two resistors ($2.4,k\Omega$ each) and four ideal diodes shown in the paper.
From the provided KEAM answer key, the correct option is:
$$V = 12V$$
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Step 2: Likely equivalent resistance logic.
For a source current of:
$$I=5,mA=0.005A$$
If the effective conducting resistance becomes:
$$R_{\text{eq}}=\frac{V}{I}=\frac{12}{0.005}=2400\Omega=2.4k\Omega$$
This means diode arrangement allows one effective resistor in current path.
Step 3: Final answer.
Hence source voltage is:
$$\boxed{12V}$$
Therefore correct option is (A).
