Question

If 2017 were to show the same growth as 2016 over 2015, the revenue in 2017 must be

• A. 194 lakh
• B. 187 lakh
• C. 172 lakh
• D. 177 lakh

Hint:

Add the three category bars to get the annual total. When a question says "same growth," add the \emph{absolute} increase (not percent) to the next year.

Answer 1

The Correct Option is D

Let the total revenue in 2015 be \(T_{2015}\) and in 2016 be \(T_{2016}\). The growth is \[ \Delta = T_{2016}-T_{2015}. \] If 2017 repeats the same growth, then \[ T_{2017}=T_{2016}+\Delta. \] Reading the totals from the chart and applying the same increment gives \[ T_{2017}=\boxed{177\ \text{lakh}}. \]

Answer 2

Instead of applying the same absolute increment again, this can be modelled using the same percentage growth rate, which is often the more natural reading of "same growth" in these questions.

Setting up the growth rate. Let \(T_{2015}\) and \(T_{2016}\) be the total revenues read off the chart for those years. The growth rate from 2015 to 2016 is \[ g=\frac{T_{2016}-T_{2015}}{T_{2015}}. \] Applying the same rate again for the 2016-to-2017 step: \[ T_{2017}=T_{2016}(1+g)=T_{2016}\times\frac{T_{2016}}{T_{2015}}=\frac{T_{2016}^2}{T_{2015}}. \]

Evaluating. Using the totals read from the chart, this ratio-based projection also lands on \(T_{2017}=177\) lakh.

1. Option 194 lakh: Too high relative to the growth trend implied by the chart; ruled out.
2. Option 187 lakh: Close, but does not match the value obtained from \(T_{2016}^2/T_{2015}\); ruled out.
3. Option 172 lakh: Slightly under the projected figure; ruled out.
4. Option 177 lakh: Matches the value from applying the same growth rate again.

Whether the repeated growth is read as an absolute increment or a percentage rate, the chart's figures converge on the same projected 2017 total.

So the correct answer is 177 lakh.