Question

If $16 \div 4 = 74$, $21 \div 7 = 33$, $81 \div 9 = 90$, then 55 $\div$ ?

• A. 110
• B. 1001
• C. 11
• D. 1011

Hint:

Look for multiplication patterns combined with additional operations like addition to solve such puzzles.

Answer 1

The Correct Option is C

Let's analyze the given pattern: - \( 16 \div 4 = 74 \) 
The pattern can be derived by multiplying the quotient by 5 and adding 1. 
\( 16 \div 4 = 4 \), then \( 4 \times 5 + 1 = 74 \). - \( 21 \div 7 = 33 \) \( 21 \div 7 = 3 \), then \( 3 \times 5 + 1 = 33 \). 
- \( 81 \div 9 = 90 \) \( 81 \div 9 = 9 \), then \( 9 \times 10 + 1 = 90 \). 
Now, applying the same pattern to 55: 
- \( 55 \div 5 = 11 \), then \( 11 \times 10 + 1 = 110 \). 
Thus, the correct answer is (C) 11. 
Therefore, the correct answer is (C) 11.