Let's observe the pattern in the given series:
3 × 2 + 1 = 7
7 × 2 + 1 = 15
15 × 2 + 1 = 31
31 × 2 + 1 = 63
63 × 2 + 1 = 127
Each term is obtained by multiplying the previous term by 2 and then adding 1.
So, the next term is:
63 × 2 + 1 = 126 + 1 = 127
Answer: 127
Find $P_1 + P_2 + \dots + P_{10}$ if $P_k$ is the perimeter of a square having side length $k$.