Question:

If 10% of the main current is to be passed through the moving coil galvanometer of resistance $99Ω$, then the required shunt resistance will be:

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$Ig G = Iₛ S$ for a galvanometer with shunt.
Updated On: Apr 16, 2026
  • 9.9 $Ω$
  • 10 $Ω$
  • 11 $Ω$
  • 9 $Ω$
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The Correct Option is C

Solution and Explanation


Step 1:
$Ig = 0.1 I$, $Iₛ = 0.9 I$.

Step 2:
$Ig G = Iₛ S → 0.1 I × 99 = 0.9 I × S → S = \frac0.1 × 990.9 = 11 Ω$.
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