Question

If 10 mL of 0.1 M sulphuric acid solution requires 20 mL of NaOH solution, then the normality of NaOH solution is:

• A. 0.1 N
• B. 0.05 N
• C. 0.2 N
• D. 0.4 N

Hint:

Use \( N_1 V_1 = N_2 V_2 \) for acid-base titrations; remember H\textsubscript{2}SO\textsubscript{4} gives 2 equivalents.

Answer 1

The Correct Option is A

Sulphuric acid (H\textsubscript{2}SO\textsubscript{4}) is diprotic, so: \[ \text{Normality of H}_2\text{SO}_4 = 2 \times 0.1 = 0.2 \text{ N} \] Using the neutralization formula: \[ N_1 V_1 = N_2 V_2 \Rightarrow 0.2 \times 10 = N_2 \times 20 \Rightarrow N_2 = 0.1 \text{ N} \]